Basic Math Examples



\begin{matrix} r = & 4 \end{matrix}

$\begin{array}{r} r = & 4 \end{array}$

Step 1

The surface area of a sphere is equal to

4

$4$ times Pi

π

$π$ times the radius squared.

4 π \cdot {(r a d i u s)}^{2}

$4 π \cdot {(r a d i u s)}^{2}$

Step 2

Substitute the value of the radius

r = 4

$r = 4$ into the formula to find the surface area of the sphere. Pi

π

$π$ is approximately equal to

3.14

$3.14$ .

4 \cdot π \cdot 4^{2}

$4 \cdot π \cdot 4^{2}$

Step 3

Multiply

4

$4$ by

4^{2}

$4^{2}$ by adding the exponents.

Tap for more steps...

Step 3.1

Move

4^{2}

$4^{2}$ .

4^{2} \cdot 4 \cdot π

$4^{2} \cdot 4 \cdot π$

Step 3.2

Multiply

4^{2}

$4^{2}$ by

4

$4$ .

Tap for more steps...

Step 3.2.1

Raise

4

$4$ to the power of

1

$1$ .

4^{2} \cdot 4^{1} \cdot π

$4^{2} \cdot 4^{1} \cdot π$

Step 3.2.2

Use the power rule

a^{m} a^{n} = a^{m + n}

$a^{m} a^{n} = a^{m + n}$ to combine exponents.

4^{2 + 1} \cdot π

$4^{2 + 1} \cdot π$

4^{2 + 1} \cdot π

$4^{2 + 1} \cdot π$

Step 3.3

Add

2

$2$ and

1

$1$ .

4^{3} \cdot π

$4^{3} \cdot π$

4^{3} \cdot π

$4^{3} \cdot π$

Step 4

Raise

4

$4$ to the power of

3

$3$ .

64 π

$64 π$

Step 5

The result can be shown in multiple forms.

Exact Form:

64 π

$64 π$

Decimal Form:

201.06192982 \dots

$201.06192982 \dots$

Enter a problem...

⎡ ⎢ ⎣ \begin{matrix} x^{2} & \frac{1}{2} \sqrt{π} & \int x d x \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$